commercial calculator in C

18CPL17/27

Program1:-

Develop a program to solve simple computational problems using arithmetic expressions and use of each operator leading to a simulation of a commercial calculator. (No built-in math function).

Concept Building

1)What is a Switch statement?
2)How many cases can you have in a switch statement?
3)What does break in switch statement indicate?
4)What is a case in a switch statement?

What is a Switch statement?

A switch statement tests the value of a variable and compares it with multiple cases. Once the case match is found, a block of statements associated with that particular case is executed.

How many cases can you have in a switch statement?

In C language we can have up to 257 cases.

What does break in switch statement indicate?

The break statement is used to terminate the switch case.

What is a case in a switch statement?

The switch statement allows a variable to be tested for equality against a list of values. Each value called a case, and the variable being switched on is checked for each switch case.

Flowchart:-

Algorithm:-

Start
Step 1: [Enter first number] read num1
Step 2: [Enter Second number] read num2
Step 3:[Enter Choice] read choice
Step 4:[To perform addition] if the choice is equal to plus add num1 and num2 print result.
Step 5: [To perform subtraction] if the choice is equal to minus subtracts num2 from num1 print result.
Step 6: [To perform multiplication] if the choice is equal to multiplication multiply num1 and num2 print result.
Step 7: [To perform division] if the choice is equal to division divide num1 by num2 print result.
Step 8: [To perform Modulus] if the choice is equal to modulus divide num1 by num2 print result (remainder)
STOP

Code in C:-

#include <stdio.h>





int main()

{

    int num1,num2,result,choice;

    printf("Enter num1 & num2: \n");

    scanf("%d %d",&num1,&num2);

    printf("Enter your choice:\n 1.Addition \n 2.Substraction \n 3.Multiplication \n 4.Divide \n 5.Reminder\n");

    scanf("%d",&choice);

    switch(choice)

    {

        case 1: result=num1+num2; break;

        case 2: result=num1-num2; break;

        case 3: result=num1*num2; break;

        case 4: result=num1/num2; break;

        case 5: result=num1%num2; break;

        default: printf("\n Invalid no\n");

    }

    printf("result is = %d",result);



    return 0;

}

***************************************************************************

OUTPUT:

First run:

Enter first number: 10

Enter second number: 20

Enter your choice:

1.Addition

2.Substraction

3.Multiplication

4.Divide

5.Reminder

Result: 10 + 20 = 30.000000

Second run:

Enter first number: 10

Enter second number: 3

Enter your choice:

1.Addition

2.Substraction

3.Multiplication

4.Divide

5.Reminder

Result: 10 / 3 = 3.333333

Third run:

Enter first number: 10

Enter second number: 3

Enter your choice:

1.Addition

2.Substraction

3.Multiplication

4.Divide

5.Reminder

9 Invalid

******************************************************************************

Video Tutorial:-

Source code Github:- https://github.com/NAJMUS7834/VTUCLAB/edit/master/Calci.c

commercial calculator in C